2ln(x)+2x^2+7=0

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Solution for 2ln(x)+2x^2+7=0 equation:


Simplifying
2ln(x) + 2x2 + 7 = 0

Multiply ln * x
2lnx + 2x2 + 7 = 0

Reorder the terms:
7 + 2lnx + 2x2 = 0

Solving
7 + 2lnx + 2x2 = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + 2lnx + -7 + 2x2 = 0 + -7

Reorder the terms:
7 + -7 + 2lnx + 2x2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 2lnx + 2x2 = 0 + -7
2lnx + 2x2 = 0 + -7

Combine like terms: 0 + -7 = -7
2lnx + 2x2 = -7

Add '-2x2' to each side of the equation.
2lnx + 2x2 + -2x2 = -7 + -2x2

Combine like terms: 2x2 + -2x2 = 0
2lnx + 0 = -7 + -2x2
2lnx = -7 + -2x2

Divide each side by '2nx'.
l = -3.5n-1x-1 + -1n-1x

Simplifying
l = -3.5n-1x-1 + -1n-1x

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